1. Subtract from this weight the before plating weight to obtain the weight of metal deposited. Post Weight – pre-weight = W
2. Calculate the average deposit thickness in inches.
W
T = ────────────────────────── = Inch
D x 13.57in² x 6.45cm²/in² x 2.54 cm/in
W= Grams of nickel deposit
D= Density of plated material g/cm³, see chart below<
T= Deposit thickness in inches
Note: The surface area for Specialty Testing spirals (helices) is 13.57 in² or 13.57 square inches.
W
T = ──────────── = _________Inch
D(222.32cm³/inch
Note: If calculation of the internal deposit stress is desired based on the pitch of the spiral (helix), since all of the Specialty Testing and Development stainless steel spirals (helices) are manufactured in the same manner from 0.0100 inch thick stainless steel, t = 0.0002540 meters, and are formed in the same manner, the pitch, p, of each spiral (helix) is 0.000254 meters. The pitch is determined by slipping a spiral (helix) over a 0.019 m, 0.75 inch, diameter rod, compressing the spiral (helix) so the edges of the loops tightly touch each other and dividing the length in meters by the number of loops. This length is 14.3 cm = 0.143 m, and 0.143m ÷ 7.73 loops equals 0.0196 m.
Note: For the spirals (helices) plated on the old design spiral contractometers, the surface area plated must be determined by wrapping the spiral (helix) tightly around a 3/4 inch diameter rod. Then the diameter and estimated plated length in inch values are used to calculate the plated surface area as follows: Surface Area = πdh = cm² b. Solve the equation for PSI internal deposit stress as follows